document.write( "Question 1134468: The length of a rectangular piece of property is one meter more than twice the width. If the perimeter of the property is 302 meters, find the length and width \n" ); document.write( "
Algebra.Com's Answer #751855 by rothauserc(4718)\"\" \"About 
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let l be the length of the rectangle and w be the width of the rectangle
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\n" ); document.write( "l = 2w +1
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\n" ); document.write( "twice the length +twice the width = perimeter of the rectangle
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\n" ); document.write( "2(2w+1) +2w = 302
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\n" ); document.write( "4w +2 +2w = 302
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\n" ); document.write( "6w = 300
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\n" ); document.write( "w = 50
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\n" ); document.write( "l = 2(50) +1 = 101
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\n" ); document.write( "length of rectangle is 101 meters
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\n" ); document.write( "width of rectangle is 50 meters
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\n" ); document.write( "2(101) +2(50) = 302
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\n" ); document.write( "202 +100 = 302
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\n" ); document.write( "302 = 302
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