document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134466>Question 1134466</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mother is four times old as Mary. Five years ago, she was seven times as old. How old will each be in five years? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #751853 by </B><A HREF=/tutors/aboutme.mpl?userid=mathsolverplus><B>mathsolverplus(88)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathsolverplus><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathsolverplus><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=751853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mother's age = x<BR>\n" );
document.write( "Mary's age = y\r<BR>\n" );
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document.write( "Present: x = 4y           Mother is four times old as Mary<BR>\n" );
document.write( "Past:   x-5 = 7(y-5)      Both age needs to be subtracted from five first.\r<BR>\n" );
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document.write( "4y-5=7y-35<BR>\n" );
document.write( " -3y=-30<BR>\n" );
document.write( "  y=10\r<BR>\n" );
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document.write( "x=40 and y=10\r<BR>\n" );
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document.write( "Mother's age in five years = 40+5 =45 years old<BR>\n" );
document.write( "Mary's age in five years = 10+5 = 15 years old \r<BR>\n" );
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