document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134427>Question 1134427</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Normally it takes John 2.5 hours to drive from his house to his office. Due to yesterday's snowy weather he was driving 10 mph slower than usually, and it took 3 hours. How many miles is the office away from John's house? Thank you for solving this problem! :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #751823 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=751823\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "You have received, so far, three responses to your question, showing similar algebraic solutions.  Here is another quite different method that I like to use on this kind of problem.<br><BR>\n" );
document.write( "The ratio of times required is 2.5:3, or 5:6.<BR>\n" );
document.write( "Since the distances are the same, that means the ratio of the speeds is 6:5.<BR>\n" );
document.write( "If the ratio of the two speeds is 6:5 and the difference between the two speeds is 10mph, then the two speeds are 50mph and 60mph.<br><BR>\n" );
document.write( "The distance is then rate times time: 2.5 hours at 60mph = 150 miles; or 3 hours at 50mph = 150 miles. </SPAN>\n" );
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