document.write( "Question 1134427: Normally it takes John 2.5 hours to drive from his house to his office. Due to yesterday's snowy weather he was driving 10 mph slower than usually, and it took 3 hours. How many miles is the office away from John's house? Thank you for solving this problem! :) \n" ); document.write( "
Algebra.Com's Answer #751811 by ankor@dixie-net.com(22740)\"\" \"About 
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Normally it takes John 2.5 hours to drive from his house to his office.
\n" ); document.write( " Due to yesterday's snowy weather he was driving 10 mph slower than usually, and it took 3 hours.
\n" ); document.write( " How many miles is the office away from John's house?
\n" ); document.write( ":
\n" ); document.write( "let s = speed normally
\n" ); document.write( "then
\n" ); document.write( "(s-10) = speed in the snow
\n" ); document.write( "the distance of both trips are the same,
\n" ); document.write( " write a distance question: dist = speed * time
\n" ); document.write( "3(s-10) = 2.5s
\n" ); document.write( "3s - 30 = 2.5s
\n" ); document.write( "3s - 2.5s = 30
\n" ); document.write( ".5s = 30/.5
\n" ); document.write( "s = 60 mph
\n" ); document.write( ":
\n" ); document.write( "Find the distance
\n" ); document.write( "2.5 * 60 = 150 mi
\n" ); document.write( "confirm the dist using the slower speed
\n" ); document.write( "3 * 50 = 150 mi
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