document.write( "Question 1134406: A man bought some chickens for ₦60. If he had obtained 5 more for the same money, they would have cost ₦2 less each. How chickens did he buy? \n" ); document.write( "

Algebra.Com's Answer #751784 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Let \"n\" be the number of chickens he bought (the value under the question).\r\n" );
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document.write( "Then the price for one chicken is  .\r\n" );
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document.write( "Had he bought (n+5) chickens for the same money, the price for one chicken in this hypothetical case would be  .\r\n" );
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document.write( "From the condition,\r\n" );
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document.write( "     -  = 2.\r\n" );
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document.write( "It is your basic equation to solve.\r\n" );
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document.write( "    Looking into the equation, you can guess its solution mentally and momentarily:  n = 10.\r\n" );
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document.write( "To solve it algebraically, multiply both sides by n*(n+5). You will get\r\n" );
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document.write( "    60*(n+5) - 60n = 2n*(n+5)\r\n" );
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document.write( "    60n + 300 - 60n = 2n^2 + 10n\r\n" );
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document.write( "    2n^2 + 10n - 300 = 0\r\n" );
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document.write( "    n^2 + 5n - 150 = 0\r\n" );
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document.write( "    (n-10)*(n+15)) = 0.\r\n" );
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document.write( "Of two roots  n= 10  and  n= -15, only positive  n= 10 is meaningful.\r\n" );
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document.write( "Answer.  n= 10 chickens.\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see many other similar solved problems, look into the lessons\r
\n" ); document.write( "\n" ); document.write( " - Challenging word problems solved using quadratic equations \r
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