document.write( "Question 1134390: The sum of 8th terms of an AP is 160 while the sum of 20 terms is 880. Find (a) the 43rd term (b) the sum of 12 terms. \n" ); document.write( "
Algebra.Com's Answer #751762 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Let a and d be the first term and common difference, respectively. Then

\n" ); document.write( "the 8th term is a+7d
\n" ); document.write( "the 20th term is a+19d

\n" ); document.write( "The sum of the first 8 terms is
\n" ); document.write( "(a)+(a+d)+(a+2d)+...+(a+7d) = 8a+28d

\n" ); document.write( "The sum of the first 20 terms is
\n" ); document.write( "(a)+(a+d)+(a+2d)+...+(a+19d) = 20a+190d

\n" ); document.write( "So

\n" ); document.write( "\"8a%2B28d+=+160\"
\n" ); document.write( "\"20a%2B190d+=+880\"

\n" ); document.write( "\"40a%2B140d+=+800\"
\n" ); document.write( "\"40a%2B380d+=+1760\"
\n" ); document.write( "\"240d+=+960\"
\n" ); document.write( "\"d+=+4\"
\n" ); document.write( "\"8a%2B112+=+160\"
\n" ); document.write( "\"8a+=+48\"
\n" ); document.write( "\"a+=+6\"

\n" ); document.write( "The first term is 6 and the common difference is 4.

\n" ); document.write( "The 43rd term is a+42d = 6+42(4) = 6+168 = 174

\n" ); document.write( "The sum of the first 12 terms is
\n" ); document.write( "(a)+(a+d)+(a+2d)+...+(a+11d) = 12a+66d = 12(6)+66(4) = 72+264 = 336
\n" ); document.write( "
\n" );