document.write( "Question 1134390: The sum of 8th terms of an AP is 160 while the sum of 20 terms is 880. Find (a) the 43rd term (b) the sum of 12 terms. \n" ); document.write( "
Algebra.Com's Answer #751762 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let a and d be the first term and common difference, respectively. Then \n" ); document.write( "the 8th term is a+7d \n" ); document.write( "the 20th term is a+19d \n" ); document.write( "The sum of the first 8 terms is \n" ); document.write( "(a)+(a+d)+(a+2d)+...+(a+7d) = 8a+28d \n" ); document.write( "The sum of the first 20 terms is \n" ); document.write( "(a)+(a+d)+(a+2d)+...+(a+19d) = 20a+190d \n" ); document.write( "So \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The first term is 6 and the common difference is 4. \n" ); document.write( "The 43rd term is a+42d = 6+42(4) = 6+168 = 174 \n" ); document.write( "The sum of the first 12 terms is \n" ); document.write( "(a)+(a+d)+(a+2d)+...+(a+11d) = 12a+66d = 12(6)+66(4) = 72+264 = 336 \n" ); document.write( " |