document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134372>Question 1134372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the circle:\r<BR>\n" );
document.write( "\n" );
document.write( "Center on line x  -  y = 6, tangent to both axes\r<BR>\n" );
document.write( "\n" );
document.write( "I changed the equation to y=x-6 and then I don't know how to solve/do the next step. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #751742 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13334)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=751742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If the circle is tangent to both axes, then the center of the circle is the same distance from both axes.  Mathematically, that means<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=abs%28y%29=abs%28x%29 ALIGN=MIDDLE  ALT=\"abs%28y%29=abs%28x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "which is equivalent to<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=x ALIGN=MIDDLE  ALT=\"y=x\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-x ALIGN=MIDDLE  ALT=\"y=-x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "So you are looking for the solution of the system<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+x-6 ALIGN=MIDDLE  ALT=\"y+=+x-6\"   DISABLED_style= \"max-width:90%; height:auto;\" > AND (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=x ALIGN=MIDDLE  ALT=\"y=x\"   DISABLED_style= \"max-width:90%; height:auto;\" > OR <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-x ALIGN=MIDDLE  ALT=\"y=-x\"   DISABLED_style= \"max-width:90%; height:auto;\" >)<br><BR>\n" );
document.write( "If you don't immediately see where the center of the circle is, here is a graph; y=x-6 (red); y = x (green); and y = -x (blue):<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28400%2C400%2C-10%2C10%2C-10%2C10%2Cx-6%2Cx%2C-x%29 ALIGN=MIDDLE  ALT=\"graph%28400%2C400%2C-10%2C10%2C-10%2C10%2Cx-6%2Cx%2C-x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "The center of the circle is at the only point where the red line intersects either the green or blue line.<br><BR>\n" );
document.write( "Then it should be clear what the radius of the circle is; and I will assume you know how to write the equation once you know the center of the circle and the radius. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );