document.write( "Question 1134088: line L1 and L2 has equation (x-3)/2 = (y-4)/-1 = (z+1)/1 and (x-5)/4 = (y-1)/3 = (z-1)/2. find Cartesian equation of the plane P which contain L1 and parallel to L2. L3 pass through point A(-3,-2,-1) and meets P at B(-1,2,1). find Cartesian equation of L3 and acute angle between P and L3 (in nearest degree). Another line L4 with Cartesian equation (x-2)/1 = (y+3)/2 = (z+2)/1 pass through plane P. find intersection point. \n" ); document.write( "
Algebra.Com's Answer #751736 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! L1: \n" ); document.write( "L2: \n" ); document.write( "\n" ); document.write( "L1 is parallel to the vector < 2,-1,1 > and passes thru (3,4,-1) \n" ); document.write( "L2 is parallel to the vector < 4,3,2 > and passes thru (5,1,1)\r \n" ); document.write( "\n" ); document.write( "find Cartesian equation of the plane P which contain L1 and parallel to L2. \n" ); document.write( " \r\n" ); document.write( "A vector perpendicular to both those lines will be perpendicular (normal) to the\r\n" ); document.write( "desired plane.\r\n" ); document.write( "\r\n" ); document.write( "So we find a vector perpendicular to both vectors by crossing them:\r\n" ); document.write( "\r\n" ); document.write( "< 2,-1,1 > × < 4,3,2 > =\r\n" ); document.write( "\n" ); document.write( " |