document.write( "Question 103362: A bus leaves a station at 1 p.m., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart? \n" ); document.write( "
Algebra.Com's Answer #75172 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
44t+48(t-1)=274
\n" ); document.write( "44t+48t-48=274
\n" ); document.write( "92t=274+48
\n" ); document.write( "92t=322
\n" ); document.write( "t=322/92
\n" ); document.write( "t=3.5 hours after the first bus leaves.
\n" ); document.write( "1+3.5=4.5 hours or 4:30 the buses will be 274 miles apart.
\n" ); document.write( "proof
\n" ); document.write( "44*3.5+48*2.5=274
\n" ); document.write( "154+120=274
\n" ); document.write( "274=274
\n" ); document.write( "
\n" );