document.write( "Question 1133874: (1+cos°)÷sin°=
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\n" ); document.write( "(1-cos°)÷(sin°-1)
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\n" ); document.write( "Sin°÷(1-cos°)
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Algebra.Com's Answer #751671 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\"%281%2Bcos%28x%29%29%2Fsin%28x%29\"\r
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\n" ); document.write( "\"1%2Bcos%28x%29=%281-cos+%5E2%28x%29%29%2F%281-cos+%28x%29%29\", using the rule: \"a-b=+%28%28a-b+%29+%28a%2Bb+%29%29%2F%28a%2Bb%29=%28a%5E2-b%5E2%29%2F%28a%2Bb%29\", we have\r
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\n" ); document.write( "\n" ); document.write( "=\"%28%281-cos+%5E2%28x%29%29%2F%281-cos+%28x%29%29%29%2Fsin%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "Use the following identity: \"1-cos%5E2%28x%29=+sin+%5E2%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"%28sin+%5E2+%28x+%29%2F%281-cos+%28x%29%29%29%2Fsin%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "=\"%28sin+%5Ecross%282%29+%28x+%29%2F%281-cos+%28x%29%29%29%2Fcross%28sin%28x%29%291\"\r
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\n" ); document.write( "\n" ); document.write( "=\"sin+%28x+%29%2F%281-cos+%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "answer:\"sin%28x%29\"÷\"%281-cos+%28x%29%29\"
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