document.write( "Question 103360: Martina leaves home at 9 a.m., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina? \n" ); document.write( "
Algebra.Com's Answer #75165 by stanbon(75887)\"\" \"About 
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Martina leaves home at 9 a.m., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?
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\n" ); document.write( "Martina DATA:
\n" ); document.write( "Rate = 24 mph ; Distance = x miles ; Time = d/r = x/24 hrs
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\n" ); document.write( "John DATA:
\n" ); document.write( "Rate = 48 mph ; Distance = x miles ; Time = d/r = x/48 hrs
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\n" ); document.write( "EQUATION:
\n" ); document.write( "Martina time = John time - 2 hrs
\n" ); document.write( "x/24 = x/48 -2
\n" ); document.write( "Multiply thru by 48 to get:
\n" ); document.write( "2x = x - 96
\n" ); document.write( "x = 96 miles
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\n" ); document.write( "Martina time = 96/24 = 4 hrs
\n" ); document.write( "9:00 + 4 hrs = 1:00 PM
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\n" ); document.write( "John will catch up to Martica at 1:00 PM
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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