document.write( "Question 1134297: Water is taken from a well 11m deep in a bucket, the rope winding on to a drum 35cm in diameter. Through what angle does the handle turn in winding up 1m of rope? If the arm of the handle is 42cm long, how far does the handle of the winder travel when bringing the bucket up from the bottom? \n" ); document.write( "
Algebra.Com's Answer #751643 by ikleyn(52788)\"\" \"About 
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document.write( "The formula   S = \"r%2Aalpha\"  for the arc length  \" S \"  via the radius \" r \" and the central angle  \" \"alpha\" \"  (in radians) works  \r\n" );
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document.write( "in both cases  when  the angle \"alpha\"  is between 0 and \"2%2Api\"  and when the angle \"alpha\"  is greater (larger) than \"2%2Api\",  describing many rotations.\r\n" );
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document.write( "For the first question, the arc length is 1 meter, the radius  r = \"0.35%2F2\" = 0.175 meters.\r\n" );
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document.write( "So, the angle  the handle turn in winding up 1 m of the rope is\r\n" );
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document.write( "    \"alpha\" = \"1%2Fr\" = \"1%2F0.175\" = 5.714 radians = 329 degrees.    ANSWER\r\n" );
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document.write( "For the second question, you may continue through this way, but more short way is to use a proportion \r\n" );
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document.write( "    \"11%2Fx\" = \"0.175%2F0.42\"\r\n" );
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document.write( "to find the distance \" x \"  the handle of the winder travel when bringing the bucket up 11 meters from the bottom.\r\n" );
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document.write( "From the proportion,  x = \"%2811%2A0.42%29%2F0.175\" = 26.4 meters.     ANSWER\r\n" );
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