document.write( "Question 1134282: Can please somebody help me solve this with explanation for a 8th grader. Thank you.\r
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document.write( "x^2-4|x|+3=0 \n" );
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Algebra.Com's Answer #751623 by Theo(13342)![]() ![]() You can put this solution on YOUR website! x^2 - 4|x| + 3 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is in between the absolute value signs.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that means that:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if x is positive, then |x| = x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if x is negative, then |x| = -x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for example, if x is euqal to 5, the |5| = 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if x is eual to -5, then |-5| = - (-5) = 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the result is that the value of x is always positive.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have two situations.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if x is positive, then x^2 - 4|x| + 3 = 0 becomes x^2 - 4x + 3 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if x is negative, then x^2 - 4(-x) + 3 = 0 which becomes x^2 + 4x + 3 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the first equation is x^2 - 4x + 3 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor this to get (x - 3) * (x - 1) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the second equation is (x + 3) * (x + 1) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the roots of the equation are x = -3, x = -1, x = 1, x = 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "those are the values of the equation when y = 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you want to graph this equation, you would look for the following intervals.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x < -3 \n" ); document.write( "x > -3 and < -1 \n" ); document.write( "x > -1 and < 1 \n" ); document.write( "x > 1 and < 3 \n" ); document.write( "x > 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you would then evaluate the equation in each of those intervals to see if it is greater than 0 or less than 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = -4, y = x^2 - 4|x| + 3 gets you y = 3 which is positive. \n" ); document.write( "when x = -2, y = x^2 - 4|x| + 3 gets you y = -1 which is negative. \n" ); document.write( "when x = 0, y = x^2 - 4|x| + 3 gets you y = 3 which is positive. \n" ); document.write( "when x = 2, y = x^2 - 4|x| + 3 gets you y = -1 which is negative. \n" ); document.write( "when x = 4, y = x^2 - 4|x| + 3 gets you y = 3 which is positive.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can now draw a rough sketch of your graph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i did the same but used graphing software found at desmos.com.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's what the graph looks like with the zero points being shown.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's what the graph looks like with the test points being shown.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "basically you're solving this the same way you solve any other absolute value problem.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have to divide the function into two parts.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the first part is when the expression in the absolute value sign is positive.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the second part is when the expression in the absolute value sign is negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "then solve each part separately. \n" ); document.write( " |