document.write( "Question 1134278: The sixth & eleventh terms of a linear sequence are respectively 23 & 48. Calculate the sum of the first twenty terms \n" ); document.write( "
Algebra.Com's Answer #751620 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The 11th term is the 6th term plus the common difference 5 times, so the common difference is

\n" ); document.write( "\"%2848-23%29%2F5+=+25%2F5+=+5\"

\n" ); document.write( "The sum of the first 20 terms of the sequence is 20 times the average of all the terms; the average of all the terms is the average of the middle two terms -- the 10th and 11th terms. Since the 11th term is 48 and the common difference is 5, the 10th term is 43; then the average of the terms in the sequence is (43+48)/2 = 91/2.

\n" ); document.write( "And so the sum of the first 20 terms is

\n" ); document.write( "\"20%2891%2F2%29+=+10%2A91+=+910\"
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