document.write( "Question 1134255: Hi\r
\n" ); document.write( "\n" ); document.write( "a rectangle has the following sides\r
\n" ); document.write( "\n" ); document.write( "the widths are x^2 & y respectively\r
\n" ); document.write( "\n" ); document.write( "the lengths are 4y+8 & 20x-16 respectively\r
\n" ); document.write( "\n" ); document.write( "one side must have an odd integer length.\r
\n" ); document.write( "\n" ); document.write( "what is the perimeter. \r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #751581 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The two widths are equal, and the two lengths are equal:
\n" ); document.write( "y = x^2
\n" ); document.write( "4y+8 = 20x-16 --> 4y = 20x-24 --> y = 5x-6

\n" ); document.write( "So

\n" ); document.write( "x^2 = 5x-6
\n" ); document.write( "x^2-5x+6 = 0
\n" ); document.write( "(x-3)(x-2) = 0

\n" ); document.write( "x could be either 3 or 2; check to see which (if either) satisfies all the conditions of the problem.

\n" ); document.write( "If x = 2 then y = x^2 = 4; the dimensions are 2 and 4. Not right -- the problem says one dimension has to be an odd integer.

\n" ); document.write( "If x = 3 then y = x^2 = 9; the dimensions are 3 and 9. This is okay; both dimensions are odd integers.

\n" ); document.write( "Now you can find the perimeter to answer the question.
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