document.write( "Question 1134246: Can someone please help? \r
\n" ); document.write( "\n" ); document.write( "The cost function for a certain company is C = 40x + 500
\n" ); document.write( " and the revenue is given by R = 100x − 0.5x2.
\n" ); document.write( " Recall that profit is revenue minus cost. Set up a quadratic equation and find two values of x (production level) that will create a profit of $500.
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Algebra.Com's Answer #751576 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
R-C=100x-0.5x^2-40x-500
\n" ); document.write( "so -0.5x^2+60x-500=0
\n" ); document.write( "solve for -0.5x^2+60x-500=500 or -0.5x^2+60x-1000=0 or x^2-120x+2000=0, multiplying the previous by -2.
\n" ); document.write( "(x-100)(x-20)=0, x=20 and 100
\n" ); document.write( "\"graph%28300%2C300%2C-30%2C300%2C-1000%2C2000%2C-0.5x%5E2%2B60x-500%2C500%29\"
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