document.write( "Question 1134246: Can someone please help? \r
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document.write( "The cost function for a certain company is C = 40x + 500
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document.write( " and the revenue is given by R = 100x − 0.5x2.
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document.write( " Recall that profit is revenue minus cost. Set up a quadratic equation and find two values of x (production level) that will create a profit of $500. \n" );
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Algebra.Com's Answer #751576 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! R-C=100x-0.5x^2-40x-500 \n" ); document.write( "so -0.5x^2+60x-500=0 \n" ); document.write( "solve for -0.5x^2+60x-500=500 or -0.5x^2+60x-1000=0 or x^2-120x+2000=0, multiplying the previous by -2. \n" ); document.write( "(x-100)(x-20)=0, x=20 and 100 \n" ); document.write( " |