document.write( "Question 1134204: solve for x. 6^(3x-4) 2^(2x+3)=648(48)^x \n" ); document.write( "
Algebra.Com's Answer #751546 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The solution using logarithms is valid, but far more work than is needed.

\n" ); document.write( "Solve the problem by putting everything in terms of prime factors.

\n" ); document.write( "\"6%5E%283x-4%29%2A2%5E%282x%2B3%29+=+648%2848%5Ex%29\"
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\n" ); document.write( "\"2%5E%285x-1%29%2A3%5E%283x-4%29+=+2%5E%284x%2B3%29%2A3%5E%28x%2B4%29\"

\n" ); document.write( "Equate the exponents of each prime factor:

\n" ); document.write( "\"5x-1+=+4x%2B3\" --> x = 4

\n" ); document.write( "and

\n" ); document.write( "\"3x-4+=+x%2B4\" --> x = 4

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