document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1134218>Question 1134218</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Carol McHugh has 3 quarters, 4 dimes, and 2 nickels in her purse. she takes one coin out of her purse without looking.\r<BR>\n" );
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document.write( "a) find the probability that carol has taken: (1) a quarter; (2) a dime; (3) a nickel<BR>\n" );
document.write( "b) show that the sum of the probabilities from part a is 1.<BR>\n" );
document.write( "c) find the probability that the coin has taken is worth: (1) less than 25 cents; (2)less than 25 cents; (3) not more than 5 cents\r<BR>\n" );
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document.write( "I understand how to do both a and b, however, got stuck with c.1,2 and 3.\r<BR>\n" );
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document.write( "thanks for helping!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #751539 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=751539\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i think part 3 will be something like this.\r<BR>\n" );
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document.write( "p(quarter) = 3/9<BR>\n" );
document.write( "p(dime) = 4/9<BR>\n" );
document.write( "p(nickel) = 2/9\r<BR>\n" );
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document.write( "total probability is 3/9 + 4/9 + 2/9 = 9/9 = 1.\r<BR>\n" );
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document.write( "you take one coin out.\r<BR>\n" );
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document.write( "the probability that it's value is greater than 25 cents is 0, since the highest value coin is 25 cents.\r<BR>\n" );
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document.write( "the probability that it's value is greater than or equal to 25 cents is 1/3 since only a quarter has a value greater than or equal to 25 cents.\r<BR>\n" );
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document.write( "the probability that it's value is less than 25 cents would be 4/9 + 2/9 = 6/9 since either a dime or a nickel would be worth less than 25 cents.\r<BR>\n" );
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document.write( "the probability that it is worth not more than 5 cents is 2/9 since only a nickel is not worth more than 5 cents.\r<BR>\n" );
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document.write( "probability of a quarter is 3/9.\r<BR>\n" );
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document.write( "probability of a dime or a nickel is 4/9 + 2/9 = 6/9.\r<BR>\n" );
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document.write( "probability of a nickel is 2/9.\r<BR>\n" );
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document.write( "a quarter is worth exactly 25 cents.\r<BR>\n" );
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document.write( "a dime or a nickel is worth less than 25 cents.\r<BR>\n" );
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document.write( "a nickel is worth exactly 5 cents.\r<BR>\n" );
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document.write( "that's what i think they are asking you.\r<BR>\n" );
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