document.write( "Question 1134201: Take a factor out of the square root:
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Algebra.Com's Answer #751507 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i'm not exactly sure waht you're looking for her.\r
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\n" ); document.write( "\n" ); document.write( "if you take the square root of (48x^2), then that could be shown as:\r
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\n" ); document.write( "\n" ); document.write( "sqrt(48 * x^2) = sqrt(48) * sqrt(x^2) = sqrt(3 * 16) * sqrt(x^2) = sqrt(3) * sqrt(16) * sqrt(x^2) = sqrt(3) * 4 * |x|.\r
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\n" ); document.write( "\n" ); document.write( "your final simplified answer would be sqrt(3) * 4 * |x|.\r
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\n" ); document.write( "\n" ); document.write( "x can be any real value.\r
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\n" ); document.write( "\n" ); document.write( "for example:\r
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\n" ); document.write( "\n" ); document.write( "when x = -5, sqrt (48 * x^2) = sqrt(48 * 25) = sqrt(1200) = 34.64101615.\r
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\n" ); document.write( "\n" ); document.write( "sqrt(3) * 4 * |x| = sqrt(3) * 4 * |-5| = sqrt(3) * 4 * 5 = 34.64101615.\r
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\n" ); document.write( "\n" ); document.write( "something to keep in mind.\r
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\n" ); document.write( "\n" ); document.write( "if x^2 = 25, then x = plus or minus 25, but sqrt(25) is always equal to 5 and not -5.\r
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\n" ); document.write( "\n" ); document.write( "here's a reference.\r
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\n" ); document.write( "\n" ); document.write( "https://www.physicsforums.com/threads/a-proof-for-sqrt-x-2-x.316896/\r
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\n" ); document.write( "\n" ); document.write( "here's another reference.\r
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\n" ); document.write( "\n" ); document.write( "https://socratic.org/questions/what-is-the-square-root-of-x-squared\r
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\n" ); document.write( "\n" ); document.write( "here's another reference.\r
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\n" ); document.write( "\n" ); document.write( "https://www.mathsisfun.com/algebra/square-root.html\r
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