document.write( "Question 1130907: Pennies are stacked on a table so that on the first day there is one penny in the stack and each day after that the number of pennies in the stack is doubled. On what day will the stack contain more than $1.00 worth of pennies? \n" ); document.write( "

Algebra.Com's Answer #751381 by Shin123(626) $\"\"$ $\"About$

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On day 1, there are 2^0 pennies. On day 2, there are 2^1 pennies. And so on. So basically, on day a, there are $\"2%5E%28a-1%29\"$ pennies. So we need to find the smallest integer a such as $\"2%5E%28a-1%29%3E100\"$ . 2^6 is 64 and 2^7 is 128. If a-1 is 7, than on day 8, there is more than $1.00 worth of pennies. \n" ); document.write( "

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