document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133772>Question 1133772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The population mean and standard deviation are given below. Find the required probability and determine whether the given sample mean would be considered unusual.\r<BR>\n" );
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document.write( "For a sample of n =75, find the probability of a sample mean being greater than <BR>\n" );
document.write( "217 if μ= 216 and σ= 6.1.\r<BR>\n" );
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document.write( "For a sample of n=75​, the probability of a sample mean being greater than <BR>\n" );
document.write( "217 if μ=216 and σ= 6.1 is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #751274 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=751274\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(xbar-mean)/sigma/sqrt(n)<BR>\n" );
document.write( "=1/(6.1/sqrt(75)<BR>\n" );
document.write( "=sqrt(75)/6.1=1.42<BR>\n" );
document.write( "0.0778 is the probability, about 1 in 14.  This would be uncommon but not real unusual.  If one uses the artificial 5% significance level, it would not reach significance. </SPAN>\n" );
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