document.write( "Question 1133946: A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts of mercury​ (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 99​% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna​ sushi?
\n" ); document.write( "0.59  0.68  0.10  0.98  1.37  0.55  0.97
\n" ); document.write( "What is the confidence interval estimate of the population mean mu​?\r
\n" ); document.write( "\n" ); document.write( "_ppm < mu < _ ppm
\n" ); document.write( "​(Round to three decimal places as​ needed.) \n" ); document.write( "
Algebra.Com's Answer #751258 by Glaviolette(140)\"\" \"About 
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I calculated the sample mean and standard deviation on a graphing calculator. Because of the small sample size, a t-score should be used. The t-score for a 99% confidence level with degrees of freedom of 6 (one less than sample size) is 3.71. This is multiplied by the sample standard deviation which is divided by the sq rt of the sample size. \r
\n" ); document.write( "\n" ); document.write( "The interval is (0.19, 1.31). This means that there is a good chance that the population mean is above 1 (can be as high as 1.31). Therefore, there does appear to be evidence that the mercury level is too high.\r
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