document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133986>Question 1133986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find what percent of all four-digit numbers have repeated digits. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #751254 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=751254\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 9 * 10 * 10 * 10 = 9000 possible four-digit numbers.  That is, 9 choices for the thousands digit, 10 each for the hundreds, tens, ones digits.<BR>\n" );
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document.write( "Consider four-digit numbers with no repeats, there are<BR>\n" );
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document.write( "9 * 9 * 8 * 7 = 4536 four-digit numbers with no repeats<BR>\n" );
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document.write( "therefore, there are 9000 - 4536 = 4464 four-digit numbers with repeats<BR>\n" );
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document.write( "4464/9000 = 0.496<BR>\n" );
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document.write( "49.6 percent of all four-digit numbers have repeats<BR>\n" );
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