document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133975>Question 1133975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At a fireworks stand show, a 3 in shell is shot from a mortar at an angle of 75 degree. The height, y (in feet) , of the shell t sec after being shot from the mortar is given by the quadratic equation <BR>\n" );
document.write( "Y= - 16t^2 + 144 and the horizontal distance of the shell from the mortar, x ( in feet), is given by the linear equation x=39t. <BR>\n" );
document.write( "A) How high is the shell after 3 seconds?<BR>\n" );
document.write( "B) What is the shell’s horizontal distance from the mortar after 3 seconds? <BR>\n" );
document.write( "C) The maximum height is reached when the shell explodes. How high is the shell when it burst after 4.5 seconds?<BR>\n" );
document.write( "D) What is the shell’s horizontal distance from launching point when it explodes? ( Round to the nearest foot). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #751249 by </B><A HREF=/tutors/aboutme.mpl?userid=Glaviolette><B>Glaviolette(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Glaviolette><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Glaviolette><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=751249\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm a bit confused about the results from the equation for height that was given.  However...here is what I've come up with.<BR>\n" );
document.write( "a. t = 3 sec<BR>\n" );
document.write( "y = -16(3)^2 + 144<BR>\n" );
document.write( "y = 0 ft (The shell hits the ground at 3 seconds)<BR>\n" );
document.write( "b.  t = 3 sec<BR>\n" );
document.write( "x = 39(3)<BR>\n" );
document.write( "x = 117 ft<BR>\n" );
document.write( "c.  t = 4.5 sec (I don't agree that this is when it reaches it's maximum height since it hit the ground at 3 sec and the answer to this is negative)<BR>\n" );
document.write( "y = -16(4.5)^2 + 144 = -180 ft<BR>\n" );
document.write( "d.  x = 39(4.5) = 175.5 ft (although this doesn't make sense based on previous answers) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );