document.write( "Question 1133934: Given that p is a root of equations x^2-x-q=0 and -x^2-7x+q+8=0, find the values of p and q \n" ); document.write( "
Algebra.Com's Answer #751199 by algebrahouse.com(1659)\"\" \"About 
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x² - x - q = 0
\n" ); document.write( "-x² - 7x + q = -8 ← subtracted 8 from both sides of second equation
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\n" ); document.write( "-8x = -8 ← added the two equations
\n" ); document.write( "x = 1\r
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\n" ); document.write( "\n" ); document.write( "Since p \"is a root\", then p = 1\r
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\n" ); document.write( "\n" ); document.write( "If x = 1:
\n" ); document.write( "(1)² - 1 - q = 0 ← substituted 1 into first equation
\n" ); document.write( "1 - 1 - q = 0 ← evaluated exponent
\n" ); document.write( "-q = 0 ← subtracted
\n" ); document.write( "q = 0 ← divided each side by -1\r
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\n" ); document.write( "\n" ); document.write( "Check by putting 1 back in for x and 0 in for q into first equation
\n" ); document.write( "(1)² - 1 - 0 = 0 ← substituted 1 for x and 0 for q into 1st equation
\n" ); document.write( "1 - 1 - 0 = 0 ← evaluated exponent
\n" ); document.write( "0 = 0 checks\r
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\n" ); document.write( "\n" ); document.write( "Check by putting 1 back in for x and 0 in for q into second equation
\n" ); document.write( "-(1)² - 7(1) + 0 + 8 = 0 ← substituted 1 for x and 0 for q into 2nd equation
\n" ); document.write( "-1 - 7 + 0 + 8 = 0 ← evaluated exponent
\n" ); document.write( "0 = 0 checks\r
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\n" ); document.write( "\n" ); document.write( "p = 1 and q = 0
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