document.write( "Question 1133934: Given that p is a root of equations x^2-x-q=0 and -x^2-7x+q+8=0, find the values of p and q \n" ); document.write( "
Algebra.Com's Answer #751199 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! x² - x - q = 0 \n" ); document.write( "-x² - 7x + q = -8 ← subtracted 8 from both sides of second equation \n" ); document.write( "------------------ \n" ); document.write( "-8x = -8 ← added the two equations \n" ); document.write( "x = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since p \"is a root\", then p = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If x = 1: \n" ); document.write( "(1)² - 1 - q = 0 ← substituted 1 into first equation \n" ); document.write( "1 - 1 - q = 0 ← evaluated exponent \n" ); document.write( "-q = 0 ← subtracted \n" ); document.write( "q = 0 ← divided each side by -1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check by putting 1 back in for x and 0 in for q into first equation \n" ); document.write( "(1)² - 1 - 0 = 0 ← substituted 1 for x and 0 for q into 1st equation \n" ); document.write( "1 - 1 - 0 = 0 ← evaluated exponent \n" ); document.write( "0 = 0 checks\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check by putting 1 back in for x and 0 in for q into second equation \n" ); document.write( "-(1)² - 7(1) + 0 + 8 = 0 ← substituted 1 for x and 0 for q into 2nd equation \n" ); document.write( "-1 - 7 + 0 + 8 = 0 ← evaluated exponent \n" ); document.write( "0 = 0 checks\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = 1 and q = 0 \n" ); document.write( " To ask me a question, visit: ask.algebrahouse.com \n" ); document.write( " |