document.write( "Question 1133931: How many gallons of a 60% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 50% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #751196 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x gallons of 60% \n" ); document.write( "60 gallons of 10% \n" ); document.write( "60+x gallons in final \n" ); document.write( "x*.60+60*.10=(60+x)*.50 \n" ); document.write( ".60x+6=30+0.5x \n" ); document.write( "0.1x=24 \n" ); document.write( "x=240 gallons ANSWER \n" ); document.write( "final solution is 300 gallons of .50% or 150 gallons of pure \n" ); document.write( "Original is 240 gallons of .60 (144 gallons pure) 60 gallons .10 (6 gallons pure), which are 150 gallons \n" ); document.write( " |