document.write( "Question 1133931: How many gallons of a 60% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 50% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #751196 by Boreal(15235)\"\" \"About 
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x gallons of 60%
\n" ); document.write( "60 gallons of 10%
\n" ); document.write( "60+x gallons in final
\n" ); document.write( "x*.60+60*.10=(60+x)*.50
\n" ); document.write( ".60x+6=30+0.5x
\n" ); document.write( "0.1x=24
\n" ); document.write( "x=240 gallons ANSWER
\n" ); document.write( "final solution is 300 gallons of .50% or 150 gallons of pure
\n" ); document.write( "Original is 240 gallons of .60 (144 gallons pure) 60 gallons .10 (6 gallons pure), which are 150 gallons
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