document.write( "Question 103313: The larger of two numbers is 1 less the 3 times the smaller. The sum is 63. Find the numbers \n" ); document.write( "
Algebra.Com's Answer #75117 by doukungfoo(195)![]() ![]() You can put this solution on YOUR website! Lets call the smaller number x \n" ); document.write( "Given: the larger number is 1 less than 3 times the smaller number. \n" ); document.write( "So if the smaller number = x \n" ); document.write( "then \n" ); document.write( "the larger number = 3x-1 \n" ); document.write( "Given: their sum is 63 \n" ); document.write( "so \n" ); document.write( "Smaller number plus larger number equals 63 \n" ); document.write( "write an equation and solve for x \n" ); document.write( "x + 3x - 1 = 63 \n" ); document.write( "4x - 1 = 63 \n" ); document.write( "4x = 63 + 1 \n" ); document.write( "4x = 64 \n" ); document.write( "x = 16 \n" ); document.write( "Answer: smaller number is 16 \n" ); document.write( "use this to find the larger number \n" ); document.write( "larger number = 3x-1 \n" ); document.write( "larger number = 3(16)-1 \n" ); document.write( "larger number = 48 - 1 \n" ); document.write( "larger number = 47 \n" ); document.write( "Answer: larger number is 47 \n" ); document.write( "Check answers: \n" ); document.write( "their sum should equal 63 \n" ); document.write( "16 + 47 = 63 \n" ); document.write( "63 = 63\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |