document.write( "Question 103288: I need your help again! I can't figure out how to do the graph or solve the equation on this problem. \r
\n" ); document.write( "\n" ); document.write( "Graph the parabola (y+2)^2 + 6x + 3 = 0. Identift the vertex, focus, and the equation of the directrix. \r
\n" ); document.write( "\n" ); document.write( "Help! This has totally lost me. You guys are awesome! Thanks for the help!
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Algebra.Com's Answer #75115 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Graph the parabola (y+2)^2 + 6x + 3 = 0. Identify the vertex, focus, and the equation of the directrix.
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\n" ); document.write( "Write in vertex form:
\n" ); document.write( "(y+2)^2 = -6(x-(1/2))
\n" ); document.write( "Vertex: ((1/2),-2)
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\n" ); document.write( "4p=-6, so p =-3/2
\n" ); document.write( "Focus: ((1/2)-(3/2),-2) = (-1,-2)
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\n" ); document.write( "Directrix: x = (1/2)-(-3/2) ; x = 2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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