document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133895>Question 1133895</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (m + n) / (m - n) + (m - n) / (m + n)\r<BR>\n" );
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document.write( "Find the sum.\r<BR>\n" );
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document.write( "Not sure how to continue. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #751133 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=751133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (m + n)/(m - n) + (m - n)(m + n)\r<BR>\n" );
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document.write( "(m + n)(m + n)/(m + n)(m - n) + (m - n)(m - n)/(m + n)(m - n)  {got common denominator of (m + n)(m - n)}<BR>\n" );
document.write( "= (m² + 2mn + n²)/(m + n)(m - n) + (m² - 2mn + n²)/(m + n)(m - n) {multiplied in numerators}<BR>\n" );
document.write( "= (2m² + 2n²)/(m + n)(m - n)   {combined numerators over common denominator}<BR>\n" );
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