document.write( "Question 1133879: I am 20 years older than twice my daughter's age. How old is my daughter? \n" ); document.write( "
Algebra.Com's Answer #751128 by josmiceli(19441)\"\" \"About 
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Let \"+x+\" = my age
\n" ); document.write( "Let \"+y+\" = my daughter's age
\n" ); document.write( "\"+x+=+2y+%2B+20+\"
\n" ); document.write( "subtract \"+20+\" from both sides
\n" ); document.write( "\"+x+-+20+=+2y+\"
\n" ); document.write( "Divide both sides by \"+2+\"
\n" ); document.write( "\"+y+=+%281%2F2%29%2Ax+-+10+\"
\n" ); document.write( "In words, this is saying that my daughter's age
\n" ); document.write( "is ten years less than half my age
\n" ); document.write( "--------------------------------------------------
\n" ); document.write( "check:
\n" ); document.write( "Suppose I am 40, or \"+x+=+40+\", then
\n" ); document.write( "\"+40+=+2y+%2B+20+\"
\n" ); document.write( "\"+20+=+2y+\"
\n" ); document.write( "\"+y+=+10+\"
\n" ); document.write( "and
\n" ); document.write( "\"+y+=+%281%2F2%29%2Ax+-+10+\"
\n" ); document.write( "\"+y+=+%281%2F2%29%2A40+-+10+\"
\n" ); document.write( "\"+y+=+20+-+10+\"
\n" ); document.write( "\"+y+=+10+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );