document.write( "Question 1133863: Sue has $2.60 in dimes and nickels. If she has 11 more dimes than nickels, how many of each coin does she have? \n" ); document.write( "
Algebra.Com's Answer #751120 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "This kind of problem can be solved informally using logical reasoning.

\n" ); document.write( "(1) Set aside the 11 \"extra\" dimes. What remains is equal numbers of dimes and nickels with a total value of $2.60-$1.10 = $1.50.
\n" ); document.write( "(2) The value of one dime and one nickel is 15 cents, or $0.15.
\n" ); document.write( "(3) To make the remaining $1.50, the number of dimes and nickels required is $1.50/$0.15 = 10.

\n" ); document.write( "So there are 10 nickels and 10+11=21 dimes.
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