document.write( "Question 1133863: Sue has $2.60 in dimes and nickels. If she has 11 more dimes than nickels, how many of each coin does she have? \n" ); document.write( "
Algebra.Com's Answer #751120 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "This kind of problem can be solved informally using logical reasoning. \n" ); document.write( "(1) Set aside the 11 \"extra\" dimes. What remains is equal numbers of dimes and nickels with a total value of $2.60-$1.10 = $1.50. \n" ); document.write( "(2) The value of one dime and one nickel is 15 cents, or $0.15. \n" ); document.write( "(3) To make the remaining $1.50, the number of dimes and nickels required is $1.50/$0.15 = 10. \n" ); document.write( "So there are 10 nickels and 10+11=21 dimes. \n" ); document.write( " |