document.write( "Question 1133843: In investing $5,900 of a couple's money, a financial planner put some of it into a savings account paying 5% annual simple interest. The rest was invested in a riskier mini-mall development plan paying 13% annual simple interest. The combined interest earned for the first year was $583. How much money was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #751101 by addingup(3677)![]() ![]() You can put this solution on YOUR website! 0.05x + 0.13(5,900 - x) = 583 \n" ); document.write( "0.05x + 767 - 0.13x = 583 \n" ); document.write( "-0.08x = -184 \n" ); document.write( "x = 2,300 this is the amount invested at 5% \n" ); document.write( "5,900 - 2,300 = 3,600 this is the amount invested at 13% \n" ); document.write( " |