document.write( "Question 1133836: How many odd numbers of at most three digits can be formed using the digits 0,1,2,3,4,5 without repetitions?
\n" ); document.write( "It says the answer is 63. I have no clue how to get this answer.. Could I get some help please? \n" ); document.write( "
Algebra.Com's Answer #751094 by Alan3354(69443)\"\" \"About 
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How many odd numbers of at most three digits can be formed using the digits 0,1,2,3,4,5 without repetitions?
\n" ); document.write( "It says the answer is 63.
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\n" ); document.write( "The units digit has to be 1, 3 or 5 to be odd, that's 1 of 3
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\n" ); document.write( "Assuming leading zeroes are not allowed, eg, 025, (tho it should be specified, we should not have to make assumptions), the 100's digit for 3 digit numbers must be 1,2,3,4,or 5, but one of the odd numbers is used, so it's 1 of 4 for the 100's digit.
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\n" ); document.write( "That's 3*4 = 12 possible 3 digit odd numbers.
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\n" ); document.write( "There are 3 possible 1 digit numbers, 1, 3 & 5
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\n" ); document.write( "For 2 digit numbers:
\n" ); document.write( "The units is 1 of 3.
\n" ); document.write( "The tens digit is 1 of 6
\n" ); document.write( "3*6 = 48
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\n" ); document.write( "48 + 12 + 3 = 63 \n" ); document.write( "
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