document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133826>Question 1133826</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine K so that the first polynomial is a factor of the second.<BR>\n" );
document.write( "x+2 ; 2x^3 -3x^2 + x -K </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #751072 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=751072\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x =  -2;\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28-2%29%5E3-3%28-2%29%5E2%2B%28-2%29%2BK=0 ALIGN=MIDDLE  ALT=\"2%28-2%29%5E3-3%28-2%29%5E2%2B%28-2%29%2BK=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Solve that for K. </SPAN>\n" );
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