document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=103276>Question 103276</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of the rectangle is 9 inches shorter than it's length and twice the radius of a circle. The difference in perimeters of the two shapes is 450 inches. Find the area of the circle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #75106 by </B><A HREF=/tutors/aboutme.mpl?userid=alisttutors><B>alisttutors(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alisttutors><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=alisttutors><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=75106\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=L-9<BR>\n" );
document.write( "W=2R<BR>\n" );
document.write( "(2W+2L)-2PiR=450\r<BR>\n" );
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document.write( "You want to find Pi*R^2 which is the same as Pi*W^2/4\r<BR>\n" );
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document.write( "2W+2(W+9)-W*Pi=450<BR>\n" );
document.write( "4W+18-Pi*W=450<BR>\n" );
document.write( "(4-Pi)*W=432<BR>\n" );
document.write( "W=432/(4-Pi)<BR>\n" );
document.write( "Pi(432/(4-Pi))^2/4\r<BR>\n" );
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document.write( "Plug that puppy into a calculator and you get:<BR>\n" );
document.write( "198,916.36920088...<BR>\n" );
document.write( "or 1.98*10^5\r<BR>\n" );
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document.write( "Hmm, that is ugly - but I've checked it - let me know if it confers with your thoughts. </SPAN>\n" );
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