document.write( "Question 1133761: If the lengths of the two equal sides of an isosceles triangle are each x cm, find the length for the third side so that the triangle has maximum area. \n" ); document.write( "
Algebra.Com's Answer #751022 by ikleyn(52814)\"\" \"About 
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\n" ); document.write( "The area of any triangle is \r
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\n" ); document.write( "\n" ); document.write( "Area = \"%281%2F2%29%2Aa%2Ab%2Asin%28gamma%29\"\r
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\n" ); document.write( "\n" ); document.write( "where a and b are any two sides and \"gamma\" is the angle between them.\r
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\n" ); document.write( "\n" ); document.write( "In given case, the sides are of the length of x centimeters, and the area is maximal when the anle \"gamma\" is 90 degrees.\r
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\n" ); document.write( "\n" ); document.write( "So, the area is maximal when the triangle is isosceles right angled triangle, and then the area is \r
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\n" ); document.write( "\n" ); document.write( "\"Area%5Bmax%5D\" = \"%281%2F2%29x2\".\r
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\n" ); document.write( "\n" ); document.write( "Completed and solved.\r
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