document.write( "Question 1133723: Three circles of radius two cm overlap so that each passes through the Center of the other two. (Basically a triple Venn diagram.) What is the area of the region that would be in the middle, in cm^2? \n" ); document.write( "
Algebra.Com's Answer #750965 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Since \"AB\", \"AC\" and \"BC\" are all radii, so they are all equal, so \"ABC\" is an equilateral triangles and all the angles are \"60\" degrees.\r
\n" ); document.write( "\n" ); document.write( " area of triangle \"ABC=%281%2F2%29ab%2Asin%2860%29\"........\"a=r\",\"+b=r\"\r
\n" ); document.write( "\n" ); document.write( "\"ABC=%281%2F2%29r%5E2%2A%28sqrt%283%29%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"ABC=%28r%5E2%2Asqrt%283%29%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Now I want to know what the area of minor segment\"+AB\" is on the circle centered at \"C\":\r
\n" ); document.write( "\n" ); document.write( "segment area=\"+%2860%2F360%29%2Ar%5E2%2Api+-%28r%5E2%2Asqrt%283%29%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "segment area= \"%282%2F12%29%2Ar%5E2%2Api+-%283r%5E2%2Asqrt%283%29%29%2F12\"\r
\n" ); document.write( "\n" ); document.write( "segment area= \"%282%2Ar%5E2%2Api+-3r%5E2%2Asqrt%283%29%29%2F12\"\r
\n" ); document.write( "\n" ); document.write( "=> now\r
\n" ); document.write( "\n" ); document.write( "shadedarea=\"3%2A%282%2Ar%5E2%2Api+-3r%5E2%2Asqrt%283%29%29%2F12+%2B%28r%5E2%2Asqrt%283%29%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "shadedarea=\r
\n" ); document.write( "\n" ); document.write( "shadedarea=\"%282%2Ar%5E2%2Api+-3r%5E2%2Asqrt%283%29%29%2F4+%2B%28r%5E2%2Asqrt%283%29%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "shadedarea=\"%282%2Ar%5E2%2Api+-3r%5E2%2Asqrt%283%29+%2Br%5E2%2Asqrt%283%29%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "shadedarea=\"%282%2Ar%5E2%2Api+-2r%5E2%2Asqrt%283%29%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "shadedarea=\"%28cross%282%29%2Ar%5E2%2Api+-cross%282%29r%5E2%2Asqrt%283%29%29%2Fcross%284%292\"\r
\n" ); document.write( "\n" ); document.write( "shadedarea=\"%28r%5E2%2Api+-r%5E2%2Asqrt%283%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "shadedarea=\"%28r%5E2%2F2%29%28pi+-sqrt%283%29%29\"\r
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\n" ); document.write( "if \"r=2cm\", the area of the shaded region is:\r
\n" ); document.write( "\n" ); document.write( "\"shadedarea=%28%282cm%29%5E2%2F2%29%28pi-sqrt%283%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"shadedarea=%284cm%5E2%2F2%29%28pi-sqrt%283%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"shadedarea=+2cm%5E2%28pi-sqrt%283%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"shadedarea=2.8190cm%5E2\"\r
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