document.write( "Question 1133718: A number consist of 3 digits whose sum is 14, the middle digit is equal to the number of the other two. If you reverse its digit the original number will be lesser by 99. Find the number. \n" ); document.write( "
Algebra.Com's Answer #750964 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A number consist of 3 digits whose sum is 14, \n" ); document.write( "a + b + c = 14 \n" ); document.write( " the middle digit is equal to the sum of the other two. \n" ); document.write( "b = a + c \n" ); document.write( " If you reverse its digit the original number will be lesser by 99. \n" ); document.write( "100a + 10b + c + 99 = 100c + 10b + a \n" ); document.write( "100a - a + 10b - 10b + 99 = 100c - c \n" ); document.write( "99a + 99 = 99c \n" ); document.write( "simplify, divide by 99 \n" ); document.write( "a + 1 = c \n" ); document.write( ": \n" ); document.write( "We got 3 simple equation and 3 unknowns so this should be easy \n" ); document.write( "in the 2nd equation, replace c with a+1 \n" ); document.write( "b = a + (a+1) \n" ); document.write( "b = 2a + 1 \n" ); document.write( ": \n" ); document.write( "in the first equation replace b with (2a+1); replace c with (a+1) \n" ); document.write( "a + (2a+1) + (a+1) = 14 \n" ); document.write( "4a + 2 = 14 \n" ); document.write( "4a = 14 - 2 \n" ); document.write( "4a = 12 \n" ); document.write( "a = 3 \n" ); document.write( "then \n" ); document.write( "b = 2(3) + 1 \n" ); document.write( "b = 7 \n" ); document.write( "and \n" ); document.write( "c = 3 + 1 \n" ); document.write( "c = 4 \n" ); document.write( ": \n" ); document.write( "Check 3 + 7 + 4 = 14 and 374 + 99 = 473\r \n" ); document.write( "\n" ); document.write( " Find the number. 374 \n" ); document.write( " |