document.write( "Question 1133718: A number consist of 3 digits whose sum is 14, the middle digit is equal to the number of the other two. If you reverse its digit the original number will be lesser by 99. Find the number. \n" ); document.write( "
Algebra.Com's Answer #750962 by josgarithmetic(39618)\"\" \"About 
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\n" ); document.write( " the middle digit is equal to the number SUM of the other two.
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\n" ); document.write( "\n" ); document.write( "Original Number \"100h%2B10t%2Bu\"\r
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\n" ); document.write( "\n" ); document.write( "Description Gives \"system%28h%2Bt%2Bu=14%2Ct=h%2Bu%2Ch%2B10t%2B100u-%28100h%2B10t%2Bu%29=99%29\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify:
\n" ); document.write( "\"system%28h%2Bt%2Bu=14%2Ct=h%2Bu%2Cu=h%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Replace h+u with t in digit sum equation.
\n" ); document.write( "\"system%28t%2Bt=14%2Ch=h%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28t=7%29\"\r
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\n" ); document.write( "\n" ); document.write( "Revise the system:
\n" ); document.write( "\"system%28h%2Bu=7%2Cu=h%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"h%2B%28h%2B1%29=7\"
\n" ); document.write( "\"h%2Bh%2B1=7\"
\n" ); document.write( "\"2h=6\"
\n" ); document.write( "\"highlight_green%28h=3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Again, digit-sum equation:
\n" ); document.write( "h+t+u=14
\n" ); document.write( "\"3%2B7%2Bu=14\"
\n" ); document.write( "\"u%2B10=14\"
\n" ); document.write( "\"highlight_green%28u=4%29\"\r
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\n" ); document.write( "\n" ); document.write( "Original Number: 374
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