document.write( "Question 1133710: A distribution of values is normal with a mean of 170 and a standard deviation of 2.\r
\n" ); document.write( "\n" ); document.write( "1. Find the interval containing the middle-most 38% of scores.\r
\n" ); document.write( "\n" ); document.write( "Enter your answer using interval notation. Example: [2.1,5.6)
\n" ); document.write( "Your numbers should be accurate to 1 decimal places.
\n" ); document.write( "Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
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Algebra.Com's Answer #750951 by Boreal(15235)\"\" \"About 
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The middle 38% of scores is 19% on each side of the mean or between 0.3100 and 0.6900.
\n" ); document.write( "This is between z=-0.495 and z=+0.495
\n" ); document.write( "z=(x-mean)/sd
\n" ); document.write( "-0.495=(x-170)/2
\n" ); document.write( "-.99=x-170
\n" ); document.write( "x=169.01 lower
\n" ); document.write( "x=170.99 higher
\n" ); document.write( "[169.01, 170.99] or [169.0, 171.0]
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