document.write( "Question 1133608: Find the sample standard deviation.\r
\n" ); document.write( "\n" ); document.write( "22 29 21 24 27 28 25 36
\n" ); document.write( "

Algebra.Com's Answer #750857 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "Standard Deviation,\r
\n" ); document.write( "\n" ); document.write( "\"22\" ,\"29\" ,\"21\", \"24\" ,\"27\", \"28\", \"25\" ,\"36\"\r
\n" ); document.write( "\n" ); document.write( "First, work out the average, or arithmetic mean, of the numbers:\r
\n" ); document.write( "\n" ); document.write( "\"mu=%2822%2B29%2B21%2B24%2B27%2B28%2B25+%2B36%29%2F8=26.5\"\r
\n" ); document.write( "\n" ); document.write( "\"N+=8\"\r
\n" ); document.write( "\n" ); document.write( "Then, take each number, subtract the mean and square the result:\r
\n" ); document.write( "\n" ); document.write( "\"22-26.5=-4.5\"
\n" ); document.write( "\"29-26.5=2.5\"
\n" ); document.write( "\"21-26.5=-5.5\"
\n" ); document.write( "\"24-26.5=-2.5\"
\n" ); document.write( "\"27-26.5=0.5\"
\n" ); document.write( "\"28-26.5=1.5\"
\n" ); document.write( "\"25+-26.5=-1.5\"
\n" ); document.write( "\"36-26.5=+9.5\"\r
\n" ); document.write( "\n" ); document.write( "Square of each difference:\r
\n" ); document.write( "\n" ); document.write( "\"%28-4.5%29%5E2\", \"2.5%5E2\",\"+%28-5.5%29%5E2\", \"%28-2.5%29%5E2\",\"+0.5%5E2\", \"1.5%5E2\",\"+%28-1.5%29%5E2\", \"9.5%5E2\"=\"20.25\", \"6.25\", \"30.25\",\"+6.25\", \"0.25\", \"2.25\", \"2.25\", \"90.25\"\r
\n" ); document.write( "\n" ); document.write( "Now calculate the Variance:\r
\n" ); document.write( "\n" ); document.write( "add up the squared differences and divide by count\r
\n" ); document.write( "\n" ); document.write( "\"%2820.25%2B6.25%2B30.25%2B+6.25%2B+0.25%2B+2.25%2B+2.25%2B90.25%29%2F8=158%2F8=19.75\"\r
\n" ); document.write( "\n" ); document.write( "Lastly, take the square root of the Variance: \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"sqrt%2819.75%29=4.444097209\"->the sample standard deviation\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );