document.write( "Question 103174This question is from textbook Elementary and intermediate algebra
\n" ); document.write( ": how many gallons of a 5% acid solution should be mixed with 30 gallons of a 10% acid solution to obtain a mixture that is 8% acid? \n" ); document.write( "
Algebra.Com's Answer #75077 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
how many gallons of a 5% acid solution should be mixed with 30 gallons of a 10% acid solution to obtain a mixture that is 8% acid?
\n" ); document.write( "---------------
\n" ); document.write( "10% liquid DATA:
\n" ); document.write( "Amt = 30 gals ; amt of active ingredient = 0.10*30 = 3 gallons
\n" ); document.write( "-----------------
\n" ); document.write( "5% liquid DATA:
\n" ); document.write( "Amt = x gals ; amt of active = 0.05x gallons
\n" ); document.write( "-----------------
\n" ); document.write( "Mixture DATA:
\n" ); document.write( "Amt = 30+x gallons ; amt of active = 0.08(30+x) = 2.4 + 0.08x gallons
\n" ); document.write( "---------------
\n" ); document.write( "EQUATION:
\n" ); document.write( "active + active = active
\n" ); document.write( "3 + 0.05x = 2.4 + 0.08x
\n" ); document.write( "0.6 = 0.03x
\n" ); document.write( "x = 0.6/0.03 = 20 gallons ( amt of 5% acid solution that must be added)
\n" ); document.write( "===============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );