document.write( "Question 103174This question is from textbook Elementary and intermediate algebra
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document.write( ": how many gallons of a 5% acid solution should be mixed with 30 gallons of a 10% acid solution to obtain a mixture that is 8% acid? \n" );
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Algebra.Com's Answer #75077 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how many gallons of a 5% acid solution should be mixed with 30 gallons of a 10% acid solution to obtain a mixture that is 8% acid? \n" ); document.write( "--------------- \n" ); document.write( "10% liquid DATA: \n" ); document.write( "Amt = 30 gals ; amt of active ingredient = 0.10*30 = 3 gallons \n" ); document.write( "----------------- \n" ); document.write( "5% liquid DATA: \n" ); document.write( "Amt = x gals ; amt of active = 0.05x gallons \n" ); document.write( "----------------- \n" ); document.write( "Mixture DATA: \n" ); document.write( "Amt = 30+x gallons ; amt of active = 0.08(30+x) = 2.4 + 0.08x gallons \n" ); document.write( "--------------- \n" ); document.write( "EQUATION: \n" ); document.write( "active + active = active \n" ); document.write( "3 + 0.05x = 2.4 + 0.08x \n" ); document.write( "0.6 = 0.03x \n" ); document.write( "x = 0.6/0.03 = 20 gallons ( amt of 5% acid solution that must be added) \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |