document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133521>Question 1133521</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A box contains 9 tickets numbered 1 to 9 inclusive. If three tickets are drawn from the box one at a time<BR>\n" );
document.write( "without replacement, find the probability that they are alternately be odd, even, odd  and even, odd, even<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #750763 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=750763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 9 tickets with 4 even numbered tickets and 5 odd numbered tickets<BR>\n" );
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document.write( "a) odd, even, odd<BR>\n" );
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document.write( "Probability(P) (odd, even, odd) = (5/9), (4/8), (4/7) = 80/504 = 10/63 is approximately 0.16<BR>\n" );
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document.write( "b) even, odd, even<BR>\n" );
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document.write( "P (even, odd, even) = (4/9) * (5/8) * (3/7) = 60/504 = 10/84 = 5/42 is approximately 0.12<BR>\n" );
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