document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133501>Question 1133501</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jessica has twice as many dimes as nickels and five more quarters than nickels.  If the value of all of her coins is $4.75, how many dimes does she have?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #750752 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13208)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=750752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The other tutor has shown you a perfectly good formal algebraic solution.<br><BR>\n" );
document.write( "An informal solution using virtually the same calculations can be obtained using logical reasoning and some simple mental arithmetic.<br><BR>\n" );
document.write( "(1) Set those \"extra\" 5 quarters aside.  The remaining value is then $3.50; consisting of equal numbers of nickels and quarters, and twice that many dimes.<BR>\n" );
document.write( "(2) Consider the value of one nickel, one quarter, and two dimes; it is $0.50.<BR>\n" );
document.write( "(3) $3.50 is 7 times $0.50; so the $3.50 consists of 7 each of nickels and quarters, and twice that many dimes.<br><BR>\n" );
document.write( "So there are 14 dimes. </SPAN>\n" );
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