document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133329>Question 1133329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Answer the following about the data set. (Round to two decimal places where appropriate)\r<BR>\n" );
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document.write( "Data set I:<BR>\n" );
document.write( "3	5	6	7	9\r<BR>\n" );
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document.write( "a) The median of Data set I is: <BR>\n" );
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document.write( "b) The interquartile range (IQR) of Data set I is from _______ to ______<BR>\n" );
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document.write( "c) The mean of Data set I is: <BR>\n" );
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document.write( "d) The standard deviation of Data set I is: <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #750615 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=750615\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Numbers are in order<BR>\n" );
document.write( "Median is the middle number or 6.<BR>\n" );
document.write( "The lower half consists of 3 and 5; the first quartile is the middle of it, or 4.<BR>\n" );
document.write( "The third quartile is therefore 89.<BR>\n" );
document.write( "Std. deviation requires mean first, which is sum/5 or 6<BR>\n" );
document.write( "squared deviations from mean, added, are 4+1+0+1+4 or 10<BR>\n" );
document.write( "divide by n-1 or 4 observations, and that is 2.5<BR>\n" );
document.write( "Take the square root, which is 1.58 </SPAN>\n" );
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