document.write( "Question 1133388: Karen is twice as old as Lori. Three years from now, the sum of their ages will be 42. How old is Karen? \n" ); document.write( "
Algebra.Com's Answer #750588 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! L = Lori's age \n" ); document.write( "K = Karen's age \r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "1. K = 2L\r\n" ); document.write( "2. (K+3) + (L+3) = 42\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Re-writing (2) w/substitution for L (L=(1/2)K): \n" ); document.write( " \r\n" ); document.write( "2'. (K+3) + ((1/2)K+3) = 42\r\n" ); document.write( " (3/2)K = 36\r\n" ); document.write( " K = (2/3)(36) = 24\r\n" ); document.write( " \n" ); document.write( "--- \n" ); document.write( "Ans: \n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( " K=24 --> L=12\r \n" ); document.write( "\n" ); document.write( "In three years: 24+3 + 12+3 = 27 + 15 = 42 (ok)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |