document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133340>Question 1133340</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chef needs 6 L of a solution that is 70% sugar. He has a 30% sugar mixture and an 80% sugar mixture that he can combine to make the 70% mixture.\r<BR>\n" );
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document.write( "Let x represent the number of liters of the 30% sugar mixture and let y represent the number of liters of the 80% sugar mixture.\r<BR>\n" );
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document.write( "How many liters of each solution will he use?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #750538 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=750538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=0.30 mixture y=0.80 mixture<BR>\n" );
document.write( "x+y=6<BR>\n" );
document.write( "y=(6-x)<BR>\n" );
document.write( ".30x+.80(6-x)=6(.70), pure sugar equation<BR>\n" );
document.write( ".30x+4.8-0.80x=4.20<BR>\n" );
document.write( "-.50x=-.60<BR>\n" );
document.write( "x=1.2 liters of 30% and 6-x or y=4.8 liters of 80%.\r<BR>\n" );
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document.write( "check 70% is 4/5 of the way between 30% and 80%<BR>\n" );
document.write( "want 4/5 of the 80% and 1/5 of the 30% </SPAN>\n" );
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