document.write( "Question 1133322: Find the 3 cubic roots of unity (1 + 0i) in complex standard form.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the 0 is a zero, not a theta
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #750518 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
Assume the cube root of 1 is z, that is,
\n" ); document.write( ":
\n" ); document.write( "z = 1^(1/3)
\n" ); document.write( ":
\n" ); document.write( "now cube both sides of the =
\n" ); document.write( ":
\n" ); document.write( "z^3 = 1
\n" ); document.write( ":
\n" ); document.write( "rewrite as
\n" ); document.write( ":
\n" ); document.write( "z^3 -1 = 0
\n" ); document.write( ":
\n" ); document.write( "this cubic can be factored
\n" ); document.write( ":
\n" ); document.write( "(z-1)(z^2 +z +1) = 0
\n" ); document.write( ":
\n" ); document.write( "use quadratic formula
\n" ); document.write( ":
\n" ); document.write( "z = -1 +square root(1^2 -4**1)/2*1 = -(1/2) +i * square root(3)/2
\n" ); document.write( ":
\n" ); document.write( "z = -1 -square root(1^2 -4**1)/2*1 = -(1/2) -i * square root(3)/2
\n" ); document.write( ":
\n" ); document.write( "z = 1
\n" ); document.write( ":
\n" ); document.write( "*******************************************************************
\n" ); document.write( "The 3 cubic roots of unity (1 + 0i) in complex standard form are
\n" ); document.write( ":
\n" ); document.write( "1+0i, (-1+i*square root(3))/2, (-1-i*square root(3))/2
\n" ); document.write( "*******************************************************************
\n" ); document.write( ":
\n" ); document.write( "
\n" );