document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1133314>Question 1133314</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The nth term of a sequence is donated by 3n (2n - 1)find the sum of the first five term  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #750504 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=750504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x(n) = 3n(2n-1) = 6n^2 -3n<BR>\n" );
document.write( ":<BR>\n" );
document.write( "the first 5 terms,<BR>\n" );
document.write( ":<BR>\n" );
document.write( "3, 18, 45, 84, 135<BR>\n" );
document.write( ":<BR>\n" );
document.write( "sum of first 5 terms is 285<BR>\n" );
document.write( ":  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );