document.write( "Question 1133299: Grady is flying a kite on 50 ft of string. Its vertical distance from his hand is 10 ft more than its horizontal distance from his hand. Assuming that the string is being held 5 ft above ground level, find its horizontal distance from Grady and its vertical distance from the ground. \n" ); document.write( "
Algebra.Com's Answer #750500 by josgarithmetic(39616)\"\" \"About 
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right triangle: vertical leg x+10, horizontal leg x, hypotenuse 50 feet\r
\n" ); document.write( "\n" ); document.write( "rectangle below the right triangle: horizontal dimension x, vertical dimension 5\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B%28x%2B10%29%5E2=50%5E2\"------simplify and solve...\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28x=30%29\" by either factoring or use of solution for quadratic equation formula. This is horizontal distance from Grady to the kite.\r
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\n" ); document.write( "\n" ); document.write( "Vertical distance from the ground, \"%28x%2B10%2B5%29=x%2B15=highlight%2845%29\"
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